Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric a

Question

                    Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide:
                

                    4HCl(aq) + MnO2(s) -> MnCl2(aq)+2H2O(l) + Cl2(g)
                

                    You add 35.9 g of MnO2 to a solution containing 41.9 g of HCl.                 

                    a.) What is the limiting reactant?                 

                    Hcl or MnO2                 

                    b.) What is the theoretical yield of Cl2?                 

                    c.) If the yield of the reaction is 76.7%, what is the actual yield of chlorine?                 

Explanation / Answer

1) MnO2

2) ACCODING TO EQUATION

86GRAMS OF Mno2 gives71 grams of chlorine

35.9grams of Mno2 gives=35.9*71/86 =29.6 grams of chlorine.

3)   % of yield=   no.of moles of product produced*100/no.of moles of reactant taken

            76.7= no.of moles of product produced /   0.41

     no.of moles of product produced=76.7*0.41/100 - 0.31 moles of chlorine

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