c)Calculate the binding energy per nucleon of the helium nucleus 52 H e extra in

Question

c)Calculate the binding energy per nucleon of the helium nucleus 52He

extra info:

Calculate the binding energy E B of the nitrogen nucleus 14 7 N . Express your answer in millions of electron volts to four significant figures. Calculate the binding energy per nucleon of the nitrogen nucleus 14 7 N . Express your answer in millions of electron volts to four significant figures. Calculate the binding energy per nucleon of the helium nucleus 52He extra info: Nucleons The term nucleon refers to the particles found in the nucleus of an atom, namely protons and neutrons. A single hydrogen atom (one proton plus one electron) has a mass of 1.007825 amu . A single neutron has a mass of 1.008665 amu . Note that amu stands for "atomic mass unit" and is sometimes abbreviated with the symbol u . Mass Defect The total mass of the individual nucleons in an atom is always greater than the actual measured mass of the atom. The difference is called the mass defect. Binding Energy The mass defect of an atom corresponds to an amount of energy called the binding energy. Binding energy can be calculated using Einstein's equation, E=mc 2 ., where E is energy in joules, m is mass is kilograms, and c is the speed of light, 2.998 times 10 8

Explanation / Answer

a)proton mass ~ 1.00728 amu
neutron mass ~ 1.00866 amu
electron mass ~ electron mass = 0.000549 amu

Binding mass is:
mass of constituents - mass of atom
for nitrogen:
(7*1.00728)-(7*1.00866)-(7*0.000549) -14.003074 = 0.11235amu)

b)Binding energy is:
E=mc^2 where c is the speed of light. Nuclear physics is usually done in MeV. where 1 amu is about 931.5MeV/c^2.

So: 0.11235 * 931.5 = 104.6MeV = 1.01*10^16 amu
Binding energy per nucleon is total energy divided by number of nucleons. 104.6/14 = 7.47MeV = 8.01*10^13 amu

c)Binding mass : (2*1.00728)+(2*1.00866)+(2*0.000549) -4.002602 = 0.029538 amu

Binding energy : 0.029538*931.5 = 27.514647 Mev = 2.9*10^14 amu

Binding energy per nucleon is total energy divided by number of nucleons. 27.51/4 = 6.87 Mev = 7.37*10^13 amu

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