answer the following questions: The blank molecular orbital diagram shown here (

Question

answer the following questions:

The blank molecular orbital diagram shown here (Figure 1) applies to the valence of diatomic lithium, beryllium, boron, carbon, or nitrogen. Bonding orbitals are marked with ? or ? and antibonding orbitals with ?? or ??.

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paramagnetic diamagnetic neither The blank molecular orbital diagram shown here (Figure 1) applies to the valence of diatomic lithium, beryllium, boron, carbon, or nitrogen. Bonding orbitals are marked with ? or ? and antibonding orbitals with ?? or ??.

Explanation / Answer

part A

bond order = 1/2 x [# of e- in bonding MO's - # of e- in antibonding MO's]

Thus C2^- is 2.5

Part B
It is paramagnetic because it has an odd electron

problem 9.82

Part A

CO+ has 4 + 6 - 1 = 9 valance electron
-- 2p sigma star
-- -- 2p pi star
^v ^ 2p pi
^v 2p sigma
^v 2s sigma star
^v 2s sigma

Bond order = (7-2) / 2 = 2.5

part B
It is paramagnetic because there is an unpaired electron.

part C

The bond order of NO- is 2.0

part D

It is also paramagnetic

part E

The bond order of OF+ is 2.0.

Part F

this molecule is paramagnetic because of its spare electron.

part G

The Bond order of NeF+ is 1.0.

part H

this element appears to be paramagnetic because oxygen is, and fluorine as an element has not yet had its magnetic tendencies discovered.

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