Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

C ( m o l / L ) P ( a t m ) k ( m o l / L ? a t m ) T ( ? C ) 3.80 Solution A>>

ID: 799452 • Letter: C

Question

C
(mol/L) P
(atm) k
(mol/L?atm) T
(?C) 3.80

Explanation / Answer

A>> 1. Use The PV=nRT 2. replace The V and n( mols) by M because((Morality= Mols/ volume: (M=mol/V) ) P=nRT/v ------> P= MRT 3. change Temp 20 c -----> 20+273 = 293K P= MRT CO2: P= (8.00*10^-2 mol/L)(0.08206 mol*atm/L*K)(293k) :(( cross off all repeated units mol,L,K) and you will be left with atm P= (8.00*10^-2 M)(0.08206 mol*atm/L*K)(293k) = 1.9 atm B>>> we are looking for mols this time n=PV/RT CO2: n= (1 atm)*(1 L)/(0.08206 mol*atm/L*K)(298k) :(( cross off all repeated units atm ,L,K) and youwill be left with mols n= (1 atm)*(1 L)/(0.08206 mol*atm/L*K)(298k)= 0.041 mols of CO2 I hope that help