Consider: 2 B 5 H 9 (g) + 12 O 2 (g) ? 5 B 2 O 3 (g) + 9 H 2 O (g) ?H? reaction

Question

Consider: 2 B5H9 (g) + 12 O2 (g) ? 5 B2O3 (g) + 9 H2O (g)      ?H?reaction= - 8687 kJ. What is the enthalpy change when 0.2500 moles of B5H9 are combusted?
Answer +1737 kJ -2171 kJ -1086 kJ -6248 kJ +1422 kJ Consider: 2 B5H9 (g) + 12 O2 (g) ? 5 B2O3 (g) + 9 H2O (g)      ?H?reaction= - 8687 kJ. What is the enthalpy change when 0.2500 moles of B5H9 are combusted? Consider: 2 B5H9 (g) + 12 O2 (g) ? 5 B2O3 (g) + 9 H2O (g)      ?H?reaction= - 8687 kJ. What is the enthalpy change when 0.2500 moles of B5H9 are combusted?

+1737 kJ -2171 kJ -1086 kJ -6248 kJ +1422 kJ +1737 kJ -2171 kJ -1086 kJ -6248 kJ +1422 kJ

Explanation / Answer

-6248 kJ

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