It requires 333J to melt 1g of ice at ite melting point. The specific heat of wa

Question

It requires 333J to melt 1g of ice at ite melting point. The specific heat of water =4.184JK-1g-1 If 100g of water at 100 degree celsius are added to 200g of ice at 0 degree celsius in an insulated container, how much ice is left at the end . Thank You It requires 333J to melt 1g of ice at ite melting point. The specific heat of water =4.184JK-1g-1 If 100g of water at 100 degree celsius are added to 200g of ice at 0 degree celsius in an insulated container, how much ice is left at the end . Thank You

Explanation / Answer

heat lost by water = heat gained by ice

mass *specific heat of water * (T-0) = mass of ice converted * latent heat of fusion

100 * 4.184 *100 = X *333

X =125.64gm

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