Consider the reaction 3 C H 4 ( g ) ? C 3 H 8 ( g ) + 2 H 2 ( g ) . Part A Using
ID: 800212 • Letter: C
Question
Consider the reaction 3CH4(g)?C3H8(g)+2H2(g). Part A Using data from Appendix C in the textbook, calculate ?G? at 298 K. Express your answer using four significant figures..?G? = 128.9 kJ
Part B Calculate ?G at 298 K if the reaction mixture consists of 41atm of CH4, 0.014atm of C3H8, and 2.0 Consider the reaction 3CH4(g)?C3H8(g)+2H2(g). Consider the reaction 3CH4(g)?C3H8(g)+2H2(g). Consider the reaction 3CH4(g)?C3H8(g)+2H2(g). Part A Using data from Appendix C in the textbook, calculate ?G? at 298 K. Express your answer using four significant figures.. 128.9 Part B Calculate ?G at 298 K if the reaction mixture consists of 41atm of CH4, 0.014atm of C3H8, and 2.0
?G? = 128.9 kJ
Part B Calculate ?G at 298 K if the reaction mixture consists of 41atm of CH4, 0.014atm of C3H8, and 2.0
Explanation / Answer
dGo = dG o products - dGo reactants
dGo = 2 x dGo H2 + dGo C3H8 - 3 x dGo CH4
dGo = 2 x 0 - 24.29 + 3 x 50.45
dGo = 127.06 kJ
B) 3 CH4 -------> C3H8 + 2H2
we know that
dG = dGo + RT lnkP
dG = dGo + RT ln [ H2]2 [ C3H8] / [ CH4]3
dG = 127.06 + 8.314 x 298 x ln 0.014 x 4 x 10-4 / 68921
dG = 69.50
dG at 298 K is 69.50 kJ /mol
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