A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of

Question

A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected to a voltmeter. With the two electrodes connected together, how do the Cl A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected to a voltmeter. With the two electrodes connected together, how do the Cl A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected to a voltmeter. With the two electrodes connected together, how do the Cl A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected to a voltmeter. With the two electrodes connected together, how do the Cl A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected to a voltmeter. With the two electrodes connected together, how do the Cl- ions move? through the external circuit from Cu to Fe through the salt bridge from the Cu half-cell to the Fe half-cell in random fashion in the direction opposite to the movement of the sulfate ions together with the Cu2+ ions to form an insoluble precipitate

Explanation / Answer

through the salt bridge from the Cu half-cell to the Fe half-cell

This happens because of the fact that Fe has better oxidation potential than Cu

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