In this experiment we have used 1.0*1.0^1J/degree celcius for the heat capactiy

Question

                    In this experiment we have used 1.0*1.0^1J/degree celcius for the heat capactiy of the coffee -cup calorimeter. let us verify this number through the following                     :                 

                    Experimental procedure :                 

                    1.) Place 50ml of water at 20.0 degree celcius in the coffee cup calorimeter .                 

                    2.) Add 50 ml of hot water at 98.0 degree celcius to the calorimeter holding the cold water .                 

                    3.) The Tf of 58.0 degree celcius was obtained through the temperature time graph.                 

                                     Now, Calculate the specfic heat of the coffee cup calorimeter used in this experiment . remember that the heat lost by the hot water was gained by the cold                     water as well as the calorimeter

Explanation / Answer

s=specific heat capacity m=mass q=heat T=temperature cal=calorimeter hw=hot water cw=coldwater

Scal(Tf-Ti) +Mhw(Shw)(Tf-Ti) +Mcw(Scw)(Tf-Ti)=0

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