First, we measured the volume of the water by using the Graduated Cylinder. Seco

Question

First, we measured the volume of the water by using the Graduated Cylinder. Second, we put the measured water into the Solar vacuum tube which was 615 ml Third, we went outdoor to do the experiment which was 1/we put the Vacuum Tube (filled with water 615 ml) outside to be heated by the sun 2/we recorded the water temperature by Digital thermometer gun which was at 11:33 AM = 73.4 F (water before heated by sun) at 11:43 AM = 79.8 F at 11:48 AM = 90.0-F at 11:53 AM = 94.9 F at 11:58 AM = 97.9 F at 12:03 AM =105.6. How will you calculate heat generated by light into the vacuum tube (show the equation and describe it) Discussion: How much heat you got?, what can you do to improve heat generation in the vacuum tube? Is there any other important observation etc.

Explanation / Answer

1. Q = ms ( T1-T2)

Here Q is heat energy supplied

m= 615 ml of water will have mass of 615/1000 kg = .615 kg ( as density =1kg/litre)

c = Specific heat of substance ( water =1 cal/ gram/ F)

So total heat recieved had caused 615 grams of water from temperature to rise from 73.4F to 105.6F

So Heat Q = 615 gms x 1 x ( 105.6-73.4)

= 883.1 Cal

2. heat heat generation is 883.1 cal, To make the water more hot, we can

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