Divide into groups of two and consider the following data for the equilibrium N2

Question

Divide into groups of two and consider the following data for the equilibrium N204(g) 2 NO2 (g), K 0.00464 at 25°C Each pair should analyze one set of data, and then everyone should discuss their results with the whole group. Start by writing the equilibrium expression for the reaction, setting up an ICE table and calculating Q: A. initial moles of N204 0.250 initial moles of NO2 0 container volume-2.00 L B. initial moles of N204-0 initial moles of NO2- 0.500 container volume- 1.50L C. initial moles of N204 0.100 initial moles of NO2- 0.100 container volume-0.50L D. initial moles of N204 0.0500 initial moles of NO2 0.539 container volume 1.00 L

Explanation / Answer

   N2O4(g)   = 2NO2.

we know that

         Q= [NO2]2/[N2O4].

A .   [NO2]= mole/volume = 0/2= 0.

         [N2O2] = 0.25/2= 0.125.

          Q=[NO2]2 /[N2O2]= 0/0.125=0.

B.    [N2O2]= 0.100/0.50=0.200

          [NO2]= 0.100/0.50=0.200

           Q=    (0.200)2/0.200= 0.200

C.    [N2O2]= 0.0500/1 =0.0500

           [NO2]= 0.539/1 = 0.539

         Q=(0.539)2/0.0500=5.81042

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