8. A eukaryotic chloride channel, when open, permits cl ions to flow spontaneous

Question

8. A eukaryotic chloride channel, when open, permits cl ions to flow spontaneously across the membrane in the direction required to go toward equilibrium. Suppose that the extracellular concentration of c is 123 mM and the intracellular concentration 4 mM. is The membrane electrical potential (Av) is 0.06 inside negative outside. Assume that RT 2.479 KU/mol, and 96.5 KJ/(v)(mol). Calculate the chemical potential term of AG for transport of CI ions into the cell. transport 331 C. 6.97 e. 331 b. 8.5 d. 8.5 9. The term calculated in question 8 favors the flow of Cl ions b. Out of the cell a. nto the cell 10. Using the information provided in question 8, calculate the electrical potential term of transport for transport of CI ions into the cell. AG e. 6.97 C. 5.79 8.5 5.79 b. 6.97

Explanation / Answer

10. G = (z)(F)(Vm) where

G = (-1)(96)(0.06)

= -5.79

But, here the molecules are not moving out of the cell, but they are moving into the cell. Therefore, energy is consumed which will be equal to 5.79 KJ/mol.

Thus, the answer is D and not C.

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