To convert from a given quantity of one reactant or product to the quantity of a

Question

To convert from a given quantity of one reactant or product to the quantity of another reactant or product. First, convert the given quantity to moles. Use molar masses to convert masses to moles, and use Avogadro's number (6.02 x 10^22 particles per mole) to convert number of particles to moles. Next, convert moles of the given reactant or product to moles of the desired reactant or product using the coefficients of the balanced chemical equation. For example, in the chemical equation the coefficients tell us that 2 mol of H2 reacts with 1 mol of O2 to product 2 mol of H2O. Finally, convert moles of the desired reactant or product back to the desired units. Again, use molar masses to convert from moles to masses, and use Avogadro's number to convert from moles to number of particles. Hydrogen gas, H2, reacts with nitrogen gas, N2, to form ammonia gas, NH3, according to the equation How many grams of H2 are needed to produce 12.66g of NH3? How many molecules (not moles) of NH3 are produced from 3.83x10^-4g of H2?

Explanation / Answer

Part C

3H2 + N2 --------- 2NH3

PM(NH3)= 14g/mol+ 3*1g/mol= 17g/mol

17g ------------------ 1mol NH3

12,66g NH3 ------ X = 0,74471 moles

With the reaction, we have

3 mol H2 ------------------ 2 mol NH3

X -------------------------- 0,74471mol NH3

X= 1,1171mol H2

PM(H2)= 2*1g/mol=2g/mol

1 mol H2 ---------- 2g

1,1171mol ----------- X= 2,2341g H2

Part D:

1 mol H2 -------- 2g

X ------------------ 3,83*10-4g

X= 1,915*10-4mol H2

3molH2 --------------2 mol NH3

1,915*10-4 mol ---------X = 1,2767*-4 mol NH3

1 mol NH3 ------------ 6,02*1023 molecules NH3

1,2767*10-4mol ---------- X= 7,6855*1019 molecules

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