1.For an aqueous solution of sodium chloride (NaCl) determine the molarity of 3.

Question

1.For an aqueous solution of sodium chloride (NaCl) determine the molarity of 3.35 L of a solution that contains 161 g of sodium chloride
2.determine the volume of solution that will contain 3.93 moles of sodium chloride 3.determine the number of moles of sodium chloride in 21.85 L of the solution
1.For an aqueous solution of sodium chloride (NaCl) determine the molarity of 3.35 L of a solution that contains 161 g of sodium chloride
2.determine the volume of solution that will contain 3.93 moles of sodium chloride 3.determine the number of moles of sodium chloride in 21.85 L of the solution

2.determine the volume of solution that will contain 3.93 moles of sodium chloride 3.determine the number of moles of sodium chloride in 21.85 L of the solution

Explanation / Answer

1.

Molarity = Moles / Volume (in L)

Moles = Mass / Molar mass = 161 g / 58.5 = 2.75 mol

Given, volume = 3.35 L

Molarity = 2.75 mol / 3.35 L = 0.821 M

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2.

The molarity of the solution is 0.821 M

Given, moles = 3.93 mol

Molarity = Moles / Volume (in L)

0.821 = 3.93 / V

V = 4.79 L

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3.

Given, MOlarity of the solution = 0.821 M

Volume of the solution = 21.82 L

Molarity = Moles / Volume (in L)

0.821 M = Moles / 21.82 L

Moles = 17.91 mol

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