In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and enoug

Question

In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and enough H2SO4 to be in 10.0% excess for converting the fresh Ca(C2H3O2)2. The single pass conversion of Ca(C2H3O2)2 in the reactor is 90.0%. Determine the amount of Ca(C2H3O2)2 recycled and the production rate of C2H4O2 by performing the following steps.

What is an expression for the amount of Ca(C2H3O2)2 entering the reactor, m3, in terms of the recycled flow of Ca(C2H3O2)2, m8, and the fresh feed of Ca(C2H3O2)2,m2?

In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and enough H2SO4 to be in 10.0% excess for converting the fresh Ca(C2H3O2)2. The single pass conversion of Ca(C2H3O2)2 in the reactor is 90.0%. Determine the amount of Ca(C2H3O2)2 recycled and the production rate of C2H4O2 by performing the following steps. What is an expression for the amount of Ca(C2H3O2)2 entering the reactor, m3, in terms of the recycled flow of Ca(C2H3O2)2, m8, and the fresh feed of Ca(C2H3O2)2,m2?

Explanation / Answer

by balancing the mass,

m3 = m2 + m8 ------(1)

m4 = 0.9*m3 = 0.9(m2 + m8) ------------(2)

m8 = 0.1*m4 (90 % conversion) = 0.1(m2 + m8), rearranging this, we get

m8 = (1/9)m2

m2 is given that 535 lb/hr

Therefore m8, the amount of Ca(C2H3O2) recycled = (1/9)*535 = 59.44 lb/hr

m3 = m2 + m8 = m2 + (1/9)m2 = (10/9)m2 = 594.44 lb/hr

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