In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and enoug

Question

In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and enough H2SO4 to be in 10.0% excess for converting the fresh Ca(C2H3O2)2. The single pass conversion of Ca(C2H3O2)2 in the reactor is 90.0%. Determine the amount of Ca(C2H3O2)2 recycled and the production rate of C2H4O2 by performing the following steps

For every lb-mol of fresh Ca(C2H3O2)2 that enters the process, how many lb-moles of C2H4O2 leave the process?

Ca(C2H3O2)+ H2SO4 right arrow CaSO4 +2C2H4O2 and with the following process. In the process, you will feed 535 pounds per hour of fresh Ca(C2H3O2)2 and CaSO4

Explanation / Answer

Ca(C2H3O2)2 + H2SO4 ------> CaSO4 + 2C2H4O2

here 1 mole of Ca(C2H3O2)2 gives 2 mol of C2H4O2

1 mole of Ca(C2H3O2)2 is equal to 158 grams and 1mole acetic acid is 60 grm and 2 mol acetic acid is 120 grams

535 pounds is 242672 grams which has 1535.9 mol of Ca(C2H3O2)2 obtained as follows:

242572grams X 1 mol of Ca(C2H3O2)2 / 158 grams = 1535.9 mol

As from the equation 1 mole of Ca(C2H3O2)2 gives 2 mol of C2H4O2 therfore 1535.9 mol of Ca(C2H3O2)2 will give

1535.9 mol X 2 mol of C2H2O2 / 1 mol of Ca(C2H3O2)2 = 3071.79 mol of acetic cid

3071.79 mol acetic acid is equivalent to 3071.79 x 60 = 184307. 8 grams which is equal to 406.32 pounds.

therefore 535 pounds of Ca(C2H3O2)2 gives 406.32 pounds of acetic acid.

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