The following data were obtained for the concentration vs.time for a certain che
ID: 812760 • Letter: T
Question
The following data were obtained for the concentration vs.time
for a certain chemical reaction. Values were measured at1.00s
intervals, beginning at 0.00s and ending at 20.00s. Concentrations
in mM are:
10.00, 6.91, 4.98, 4.32, 3.55, 3.21,
2.61,2.50, 2.22, 1.91, 1.80, 1.65, 1.52, 1.36, 1.42, 1.23, 1.20,
1.13,1.09, 1.00, 0,92.
A) Plot concentration (c) vs time, ln c vs time, and 1/c
vstime.
B) Is the data 0th, 1st, or 2nd order? Calculate the
rate constant for the reaction
C) What might be an experiment method which might be used to measure the concentrations that are changing so rapidly? The reaction is over in 20 s
Explanation / Answer
Initial conc. Final conc Tine consumed Change in moles/time in sec
10.00 3.21 5 sec 6.79 mM / 5 secc = 1.358 mM/sec
10.00 1.80 10 sec 8.2 mM / 10 sec = 0.82 mM/sec
10.00 1.23 15 sec 8.77 mM/ 15 sec = 0.584 mM/sec
10.00 0.92 20 sec 9.08 mM/20 sec = 0.454 mM/sec
Change in concentrations at 5 and 10 sec Rates at 5 and 10 sec
3.21 =1.78 1.358 mM/sec = 1.65
1.80 0.82 mM/sec
So the rate is changing more or less as much concentration is chnaging. So its first order reaction
Flash photolysis combined with absorption spectroscopy can study reactions on a microsecond time scale. Laser induced fluorescence extends the measurements to nanosecond time scales
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.