HELP PLEASE!!! Calculate the root mean square velocity and kinetic energy of CO,

Question

HELP PLEASE!!!

Calculate the root mean square velocity and kinetic energy of CO, CO2, and SO3 at 258K .

*****PLEASE HELP

A.)

Calculate the root mean square velocity of CO at 258K .

Part B

Calculate the root mean square velocity of CO2 at 258K .

Part C

Calculate the root mean square velocity of SO3 at 258K .

Part D

Calculate the kinetic energy of CO at 258K .

Part E

Calculate the kinetic energy of CO2 at 258K .

Part F

Calculate the kinetic energy of SO3 at 258K .

Part G

Which gas has the greatest velocity?

Part H

The greatest kinetic energy?

Part I

The greatest effusion rate?

Explanation / Answer

the molar gas constant "R", has the value 8.3143 J/mol K,
and the temperature "T", is in Kelvin.
Since the joule is the kg-m2/s2, the molar mass must be in kg/mol

vrms = (the square root of)3RT/M,

vrms CO = [(3)(258K)(8.3143 J/mol K) / (0.02801 kg/mol)]^1/2 = 482.6 m/sec

vrms CO2 = [(3)(258K)(8.3143 J/mol K) / (0.04401 kg/mol)]^1/2 = 384.47 m/sec

vrms SO3 = [(3)(258K)(8.3143 J/mol K) / (0.08006 kg/mol)]^1/2 = 285.31 m/sec
======================================...
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K.E. = 1/2 (mass) (velocity)2 or
= 3/2 RT Joules/mole
= 1.5 (8.314 J/mol-K)(255K)
= 13.78 joules per mole

your answer is: 13.8 J/mole is the average K.E. for any of the three gases

the velocity can be compared taking account of the mass of different gases.

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