create a simple graphic indicating the distance in map units between the genes s
ID: 8134 • Letter: C
Question
create a simple graphic indicating the distance in map units between the genes studied.Chromosome map. Make sure your map is correct with respect relative distance. Use a key such as 1 cm = 1 map unit.
1. determine the map distance between the linked genes for eye color and wing type in the following experiment:
Preform the following cross, PpVv x ppvv.You count 1000 offspring in the F1 generation. you find that 406 of the flies have normal eyes and normal wings, 398 have purple eyes and vestigial wings, 96 have normal eyes and vestigial wings, and 100 have purple eyes and normal wings.
2. From the previous research findings, you know that the distance between the gene for eye color and the gene for the body color is 12.2 map units, and the gene for the body color is 7.4 map units away from the gene for wing type. all three genes are on the same chromosome. Draw a chromosome map showing the relative distances between the three linked genes.
Explanation / Answer
PpVv x ppvv
Parental ---------804
406 ---normal eyes and normal wings,
398 -------purple eyes
Recombinants --------196
96 -----normal eyes and vestigial wings,
100 ----------- purple eyes and normal wings.
Total =406+398+96 +100=
% of Recombinancy = Recombinants/total x 100
=196/1000 = 0.196=0.19
The distance between P and V genes is 19.6 map units .
distance between the gene for eye color and the gene for the body color is 12.2 map units, and the gene for the body color is 7.4 map units away from the gene for wing type.
e--------------12.2 map units ---------------------b--------7.4 map units ------------------w
total map distance -12.2+7.4= 19.6.
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