3. Consider the following orbital diagram and then answer the questions below. W

Question

3. Consider the following orbital diagram and then answer the questions below. What element is this? What type of compound is this element most likely to form? Why? c) What do you expect would he the charges on the most common ions this clement is likely to form in a chemical reaction with another clement? Explain how you determined this, and write the valence electron configuration of each ion. Is this element paramagnetic or diamagnetic? Justify your choice. 4. (3 pts) a) Rank the following elements according to increasing first ionization energy, and provide a brief justification of your ranking: Ne Li B N F C O Be b) Rank the following elements according to increasing second ionization energy, and provide a brief justification of your ranking: Ne Li B N F C O Be c) Rank the following elements according to increasing electron affinity, and provide a brief justification of your ranking: Ne Li B N F C O Be

Explanation / Answer

3)

a) Iron (Fe)

b) it forms Ionic compound. because it is high electro positive element. and it can loose electrons easily    Ex: FeO, Fe3O4, FeSO4

c) it can form two types of ions Fe+2 and Fe+3. in these most stable ion is Fe+3 .it is due to half filled electronic configuration [Ar] 3d5

   example compounds : FeCl3, Fe3O4

d) both Fe+2 and Fe+3 are para magnetic in nature. it is due to presence of unpaired electrons

magnetic moment = sqrt(n(n+2))

   for Fe+2   magnetic moment= 4.8BM , for Fe+3 magnetic moment = 5.9BM

4)

a) Li< Be> B<C<N>O<F<Ne

   here Be IP value is more than B . it is due to full filled 2S orbital

     N    IP value is more than O. because hallfilled 2P orbital

b) Li> Be< B>C<N<O<F<Ne

      Li , and B has greater IP value due to full filled 1S of Li and full filled 2S of B

c) Li<Be< B<C<N<O<F<Ne

    EA increasee from left to right in periods . due to valance electrons added to same shell

     

    

   

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