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Hi, I\'m doing a lab report in which I\'m trying to determine the Ksp of calcium

ID: 813872 • Letter: H

Question

Hi, I'm doing a lab report in which I'm trying to determine the Ksp of calcium hydroxide. I'm stuck on the following part:

Determine the molar concentration of dissolved hydroxide ions in the saturated Ca(OH)2 solution.

In the experiment I used 25 mL 0.050 M HCl solution and added it to 15 mL saturated Ca(OH)2 solution until the equivalence point was reached. I collected the following data from the experiment:

Please help! thank you!

Trial Equivalence Point (mL HCl 1 13.97 mL 2 13.15 mL Average 13.56 mL

Explanation / Answer

I cannot see correctly the information you posted, but anyway some things can be told (and I hope they may help you!)

You were trying to determine the Ksp of calcium hydroxide and to do that you titrated 15 mL saturated Ca(OH)2 solution until the equivalence point was reached using 25 mL 0.050 M HCl.

To calculate the Ksp = [Ca+2 ] [OH-]2 you have to:

I hope It have helped you! :)

Ma x Va = Mb x Vb (b = before the titration, a = after the titration)

Ksp = [Ca2+] [OH-]2

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