Percent Yield The Haber-Bosch process is a very important industrial process. In

Question

Percent Yield The Haber-Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation The ammonia produced in the Haber-Bosch process has a wide range of uses. from fertilizer to pharmaceuticals. However. the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation. 1.83g H2 is allowed to react with 9.60g N2, producing 1.97g NH3. Part A What is the theoretical yield for this reaction under the given conditions? Part B What is the percent yield for this reaction under the given condition?

Explanation / Answer

3H2 + N2 ------> 2NH3

a>1.83gH2= 1.83 /2 =0.915 mol

9.60g N2=9.60/28 =.343 mol

3mol react with 1mol to form 2mol NH3

1                    1/3              2/3

.915              1/3x0.915=.304   2x0.304=0.608 molNH3 formed

b>1.97gNH3=0.1158 mol

% yelid = .1158x100/0.608=19.04%

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.