Compound A has a partition coefficient (K) of 7 when comparing its solubility in

Question

Compound A has a partition coefficient (K) of 7 when comparing its solubility in CH2Cl2 to water (k=7=[solubility in g/mL in CH2Cl2] divided by [solubility in g/mL in H2O]). If we take 8.0g of A and partition it thoroughly between 50mL of CH2Cl2 and 100mL of water, what is the equation which will tell us how much of A (which is presented by x) is in the water layer after this partitioning?

a. 8.0 =[(7-x)/50] divided by [(x/100)]

b. 7.0 =[(8.0-x)/(x/100)] divided by [50]

c. 7 =[(8.0-x)/(100/x)] divided by [50]

d. 8.0 =[(7-x)/50] divided by [(100/x)]

e. 7.0 =[(8.0-x)/50] divided by [(x/100)]

Explanation / Answer

Answering method

partition coefficient = [Solute] solvent2 / [Solute] solvent1

therefore answer is e)

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