A schematic of the facility is shown in Figure 1 on page 2. Due to the difficult
ID: 815727 • Letter: A
Question
A schematic of the facility is shown in Figure 1 on page 2. Due to the difficulty (and cost) of achieving high purity, the input streams (F1 and F2) both contain significant concentrations of CO2. The input feeds (F1 and F2) are blended to achieve a
stoichiometric ratio of H2S and SO2 and are subsequently combined with a recycle stream and fed into the reactor. The solid sulfur is completely removed in the solids separator while the water is completely removed in a condenser. The stream leaving the condenser splits into a purge stream and the recycle stream. The flow rate in F1 is 100 mol/sec and the process achieves a 95% conversion of H2S. In addition, the recycle to feed ratio is R/f0=15
a)What is the flow rate at F0? Please include the overall flow rate and the individual component flow rates. (One Question, not multiple)
A schematic of the facility is shown in Figure 1 on page 2. Due to the difficulty (and cost) of achieving high purity, the input streams (F1 and F2) both contain significant concentrations of CO2. The input feeds (F1 and F2) are blended to achieve a stoichiometric ratio of H2S and SO2 and are subsequently combined with a recycle stream and fed into the reactor. The solid sulfur is completely removed in the solids separator while the water is completely removed in a condenser. The stream leaving the condenser splits into a purge stream and the recycle stream. The flow rate in F1 is 100 mol/sec and the process achieves a 95% conversion of H2S. In addition, the recycle to feed ratio is R/f0=15 a)What is the flow rate at F0? Please include the overall flow rate and the individual component flow rates. (One Question, not multiple)Explanation / Answer
The reaction required to form solid sulfur is as follows:
2H2S + SO2 = 3S + 2H2O
Therefore, the stoichiometric ratio is 2 mol of H2S per mol of SO2. If the flow in F1 is 100 mol / sec with 90% of H2S, there are 90 mol / sec of H2S in F1. To achieve shoichiometric ratio (2:1), we need 45 mol / sec of SO2, and if F2 is made up of 95% of SO2, then:
45 mol / sec ---- 95%
x -------------- 100%
x= 47.37 mol / sec (F2 flow)
Subsequently:
100 mol / sec + 47.37 mol / sec = 147.37 mol / sec total in F0
If the Recycle / Feed ratio is 15, then:
Recycle / (147.37 mol / sec) = 15
Recycle = 15 ( 147.37 mol / sec )
Recycle = 2210.55 mol / sec.
If the flow that comes out of the condenser is equally split into R (recycle) and P (purge), we can assume that P also has a flow of 2210.55 mol / sec.
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