A particular reactant decomposes with a half-life of 109 s when its initial conc

Question

A particular reactant decomposes with a half-life of 109 s when its initial concentration is 0.274 M. The same reactant decomposes with a half-life of 231 s when its initial concentration is 0.129 M.

A particular reactant decomposes with a half-life of 109 s when its initial concentration is 0.274 M. The same reactant decomposes with a half-life of 231 s when its initial concentration is 0.129 M. A particular reactant decomposes with a half-life of 109 s when its initial concentration is 0.274 M. The same reactant decomposes with a half-life of 231 s when its initial concentration is 0.129 M. Determine the reaction order. What is the value and unit of the rate constant for this reaction? K= Number Select answer

Explanation / Answer

Values:

Half-Life time: 109 seg at [A]=0.274 M

Half-Life time: 231 seg at [A]=0.129 M

PROCESS:

Order Tipes:

[A]=[A]o - kt (Zeroth order tipe)

Ln [A]=Ln [A]o - kt (First order tipe)

Ln 1/[A] = Ln 1/[A]o + kt (Second order tipe)

IF:

Time to pass 100%[A]o at 50%[A]o is 109 seg. for [A]o=0.274M [A]=0.137M

THEN:

0.137M = 0.274M + kt

0.137M - 0.274M = kt

(0.137M - 0.274M)/t = k

k = (0.137M - 0.274M)/109 seg

k = -0.137 moL.L-1/109 seg

k = -1.26x10-3 moL.L-1.seg-1

Answer:

K(value)= -1.26x10-3 moL.L-1.seg-1

(Correspond at zeroth order reaction)

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