Please help thank you In the Slinky Dog, heritability for the maximum stretched

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In the Slinky Dog, heritability for the maximum stretched size of the body is estimated from a population as h^2 = 0.5. A change in the pattern of sexual selection in this environment favors a shift to a larger maximum size, from the current average of 100cm to a new mean of 250cm. Using the breeder's equation R = h^2S (where R is the response to selection and S is the selection differential), how many generations will the population take to get to the new optimum with a selection differential of 100cm? You can assume that the heritability does not change over time. a) 1.5 generations. a) based on the information given, you cannot calculate the answer. b) 1.5 generations. c) 3 generations.

Explanation / Answer

Answer: 3 generations (As explained below)

h2 = R / S = (avg of current gen - avg of next gen) / (avg of current gen - avg of selected parents)

Now h2 = 0.5 = 1/2 and let avg of next gen be Z.

Using this, we have:

1/2 = (100 - Z) / (100 - 200) => -100 = 200 - 2Z => 2Z = 300 => Z = 150 -----------This is the result after the first gen.

Using this for the next gen, we have:

1/2 = (150 - Z) / (150 - 200) => -100 = 300 - 2Z => 2Z = 400 => Z = 200 -------This is the result after the second gen.

Using this for the subsequent gen, we have:

1/2 = (200 - Z) / (200- 300) => -100 = 400 - 2Z => 2Z = 500 => Z = 250 -------This is the result after the three gen.

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