e. How many grams of HCl are produced when 2.5 kg C12H4Cl6 react? Please help an

Question

e. How many grams of HCl are produced when 2.5 kg C12H4Cl6 react?

Please help and explain calculations.

The decomposition of PCBs can be represented by the equation: 2Cl2H4Cl6 + 23O2 + 2H2O rightarrow 24CO2 + 12HCl Answer parts (a) through (e) below: How many moles of water are needed to react 10.0 mol O2? How many grams of HCl are produced when 15.2 mol H2O react? How many moles of CO2 are produced when 76.5 g HCl are produced? How many grams of C12H4Cl6 are reacted when 100.25 g CO2 are produced?

Explanation / Answer

a)

Moles of H2O = 10.0 moles of O2 x 2 moles of H2O / 23 moles of O2 = 0.870 moles

b)

Moles of HCl = 15.2 moles of H2O x 12 moles of HCl / 2 moles of H2O = 91.2 moles

Mass of HCl = 91.2 moles x 36.46 g / mol = 3.33 x 10^3 g

c)

Moles of HCl = 76.5 g x 1 mol / 36.46 g = 2.10 moles

Moles of CO2 = 2.10 moles of HCl x 24 moles of CO2 / 12 moles of HCl = 4.2 moles

d)

Moles of CO2 = 100.25 g x 1 mol / 44.01 g = 2.28 moles

Moles of C12H4Cl6 = 2.28 moles of CO2 x 2 moles of C12H4Cl6 / 24 moles of CO2 = 0.19 moles

Mass of C12H4Cl6 = 0.19 moles x 360.88 g / mol = 68.6 g

e)

Mass of C12H4Cl6 (in g) = 2.5 kg x 1,000 g / 1 kg = 2,500 g

Moles of C12H4Cl6 = 2,500 g x 1 mol / 360.88 g = 6.93 moles

Moles of HCl = 6.93 moles of C12H4Cl6 x 12 moles of HCl / 2 moles of C12H4Cl6 = 41.6 moles

Mass of HCl = 41.6 moles x 36.46 g / mol = 1.52 x 10^3 g

Hope this helps and good luck! :)

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