7 Marks: 1 The activation energy for the isomerization ol cyclopropane to propen

Question

7 Marks: 1
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.) 7 Marks: 1 Marks: 1
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.)
The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this reaction increase as the temperature rises from 232 to 291 oC? (The factor is the ratio of the rates.)

Explanation / Answer

ln(k1/k2)=-Ea/R(1/T1-1/T2)

or ln(x)=-(274*10^3/8.31)*(1/(273+232) - 1/(273+291))

or x=0.00108

so factor=x^-1

=925.342

Related Questions

Navigate

• Browse (All)
• Browse 7
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.