need help on chem homework and I am confused Elemental S reacts with O2 to form

Question

need help on chem homework and I am confused

Elemental S reacts with O2 to form SO3 according to the reaction 2S + 3O2 rightarrow 2SO3 as depicted here.(Figure 1) How many O2 molecules are needed to react with 3.54g of S? Express your answer numerically in units of molecules. Incorrect; Try Again You calculated the number of moles of S in 3.54g . You need to find the number of molecules of O2 needed to react with 3.54g of S. What is the theoretical yield of SO3 produced by the quantities described in Part A? Express your answer numerically in grams.

Explanation / Answer

(A) 2 S + 3 O2 => 2 SO3

Moles of S = mass/molar mass of S

= 3.54/32.07 = 0.1104 mol


Moles of O2 = 3/2 x moles of S

= 3/2 x 0.1104 = 0.1656 mol


Number of O2 molecules = moles x molar mass of O2

= 0.1656 x 6.022 x 10^23

= 9.97 x 10^22 molecules


(B) Moles of SO3 = moles of S = 0.1104 mol


Theoretical yield = moles x molar mass of SO3

= 0.1104 x 80.06

= 8.84 g

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