Currently wokring on Chemistry homework and I am totally stuck on numbers 5 & 6

Question

Currently wokring on Chemistry homework and I am totally stuck on numbers 5 & 6 please help anyone. I have posted images. Thank you! If the image appears to hard to read, please right click on it and save image or open link in another webpage to get full size.

Use your lab data (column 1 of the table below) to determine the densities and concentrations and fill in your results. (The mass of your sucrose was 15.58 g and you were working with 50.00 ml. of solution.) Make a graph of your calculations in Question #1, concentration (x-axis, in M) versus density (y-axis, in g/mL), and determine the formula for the best-fit line (in y=mx + b format). What is the slope of the best-fit line? What is the y-intercept of the best-fit line? Calculate the density of your unknown sucrose solution for each of the three trials and enter these values in the table below. Your results are listed column 1. (You were working with 10.00 ml. of solution.) Determine the average density of your unknown and the standard deviation. Enter the average density of your unknown sucrose solution. Enter the standard deviation of your unknown sucrose solution. Use your average density and your graph of density versus concentration (and best-fit line) to determine the concentration of your unknown solution. Note: it is possible to receive only half credit for this question if your calculations are correct but your data lead to inaccurate results. Once your answer has been accepted, it cannot be changed your data will not be accepted. Use your average and standard deviation, along with your graph of density versus concentration (and best-fit line) to determine the range of concentrations of your unknown solution (within one standard deviation). The concentration of the unknown sucrose solution is between

Explanation / Answer

5) in graph of density vs concentration (best fit line) draw the horizontal line of average density and concentration of your unknown solution is intersection point...i.e 0.0264 M

6) lower limit= 0.0214

upper limit = 0.0314

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