Question 1 : Given the following reactions and standard molar enthalpy changes ?

Question

Question 1: Given the following reactions and standard molar enthalpy changes ?rH0:

D-glucose 6-phosphate2-(aq) = D-fructose 6-phosphate2-(aq)                                (1)

D-glucose + ATP4-(aq) = D-glucose 6-phosphate2-(aq) + ADP3-(aq) + H+(aq)         (2)

D-fructose + ATP4-(aq) = D-fructose 6-phosphate2-(aq) + ADP3-(aq) + H+(aq)        (3)

?rH0 (1) = 11.7 kJ mol-1

?rH0 (2) = -23.8 kJ mol-1

?rH0 (3) = -15.0 kJ mol-1

Calculate ?rH0 for the reaction: D-glucose(aq) = D-fructose(aq)                  (4)

Explanation / Answer

Subtracting equations 2 and 3 we get the required equation . So answer is -23.8 - (-15.0) = -8.8KJ mol-1

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.