If 2.15g of an unknown solid nonelectrolyte is dissolved in 18.6gof naphthalene,

Question

If 2.15g of an unknown solid nonelectrolyte is dissolved in 18.6gof naphthalene, the resulting solution is found experimentally tofreeze 4.3 degrees Celsius lower than pure naphthalene. If thefreezing point depression constant for naphthalene is 6.85 degreesCelsius per mole (C/m), calculate each of the following:
a) The molality of the solution by using only the freezing pointdepression and the freezing point depression constant.
b) The number of moles of unknown dissolved in the 10.1g ofnaphthalene using the mass of naphthalene and the molality of theunknown.
c) The molar mass of the unknown
d) The molecular formula of the unknown if it is comprised of 40.0%carbon, 6.7% hydrogen and 53.3% oxygen.
e)Why is it important to specify that the unknown is anonelectrolyte?

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Explanation / Answer

?TF = Kf

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