A compound formula XCl3 reacts with aqueous AgNO3 to yield solid AgCl according

Question

A compound formula XCl3 reacts with aqueous AgNO3 to yield solid AgCl according to the following equation:
XCl3(aq)+3AgNO3(aq)?X(NO3)3(aq)+3AgCl(s)

When a solution containing 0.521g of XCl3 was allowed to react with an excess of aqueous AgNO3, 1.68 g of solid AgCl was formed.
What is the identity of the atom X? Express your answer as a chemical formula. A compound formula XCl3 reacts with aqueous AgNO3 to yield solid AgCl according to the following equation:
XCl3(aq)+3AgNO3(aq)?X(NO3)3(aq)+3AgCl(s)

When a solution containing 0.521g of XCl3 was allowed to react with an excess of aqueous AgNO3, 1.68 g of solid AgCl was formed.
What is the identity of the atom X? Express your answer as a chemical formula.

Explanation / Answer

1.68 AgCl = 1.68/143.32 = 0.011722

for every mole of XCl3 3 AgCl moles are formed

hence moles of XCl3 = 0.011722/3 = 0.00391

XCl3 mass given 0.521 gm

hence XCl3 molar mass = mass/moles = 0.521/0.00391 = 133.25

X + 3Cl mol mass = 133.25 gm/mol

X atomic mass + 3( 35.5) = 133.25

X atomic mass = 26.75 gm/mol

hence X = Aluminium = Al

XCl3 = AlCl3

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