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ID: 821033 • Letter: #

Question

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Explanation / Answer

let x mols of PCl5 reacted

then final concentrations are

concentration of PCl5 initially = .143/2.35 = .0608

.0608 - x   , x,x


Kc = x^2/.143 -x


solving we get x = .06


cocentration of PCL5 = .0008

PCl3 = .06