help. The reaction between potassium superoxide, KO2 , and C02, 4K02 + 2C02 righ

Question

help.

The reaction between potassium superoxide, KO2 , and C02, 4K02 + 2C02 rightarrow 2K2C03 + 302 is used as a source of 02 and absorber of C02 in self-contained breathing equipment used by rescue workers. (Figure 1) How many moles of 02 are produced when 0.325mol of K02 reacts in this fashion? Express your answer with the appropriate units. How many grams of KO2 are needed to form 8.5g of O2? Express your answer with the appropriate units. How many grams of CO2 are used when 8.5g of O2 are produced? Express your answer with the appropriate units.

Explanation / Answer

(A) 4 KO2 + 2 CO2 => 2 K2CO3 + 3 O2

Moles of O2 = 3/4 x moles of KO2

= 3/4 x 0.325

= 0.24375 mol = 0.244 mol


(B) Moles of O2 = mass/molar mass of O2

= 8.5/32.00 = 0.265625 mol


Moles of KO2 = 4/3 x moles of O2

= 4/3 x 0.265625 = 0.35417 mol


Mass of KO2 = moles x molar mass of KO2

= 0.35417 x 71.097

= 25.2 g = 25 g


(C) Moles of CO2 = 2/3 x moles of O2

= 2/3 x 0.265625 = 0.17708 moo


Mass of CO2 = moles x molar mass of CO2

= 0.17708 x 44.01

= 7.79 g = 7.8 g

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