Write the dissociation reaction and the corresponding K a equilibrium expression

Question

Write the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (For the dissociation reaction, include states-of-matter under the given conditions in your answer. Use the lowest possible whole number coefficients. Concentration equilibrium expressions take the general form: Kc = [HCl]2 / [H2] . [Cl2].)

(a)    HC7H13O2(aq)
dissociation reaction:

equilibrium expression:

(b)    Cr(H2O)63+
dissociation reaction:

equilibrium expression:

(c)    C3H7NH3+
dissociation reaction:

equilibrium expression:

Explanation / Answer

(a) HC7H13O2(aq) <=> C7H13O2-(aq) + H+(aq)

or HC7H13O2(aq) + H2O(l) <=> C7H13O2-(aq) + H3O+(aq)


Ka = [C7H13O2-][H+]/[HC7H13O2]

or Ka = [C7H13O2-][H3O+]/[HC7H13O2]


(b) Cr(H2O)63+(aq) <=> Cr(H2O)5(OH)2+(aq) + H+(aq)

or Cr(H2O)63+(aq) + H2O(l) <=> Cr(H2O)5(OH)2+(aq) + H3O+(aq)


Ka = [Cr(H2O)5(OH)2+][H+]/[Cr(H2O)63+]

or Ka = [Cr(H2O)5(OH)2+][H3O+]/[Cr(H2O)63+]


(c) C3H7NH3+ <=> C3H7NH2(aq) + H+(aq)

or C3H7NH3+(aq) + H2O(l) <=> C3H7NH2(aq) + H3O+(aq)


Ka = [C3H7NH2][H+]/[C3H7NH3+]

or Ka = [C3H7NH2][H3O+]/[C3H7NH3+]

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