Benzene and toluene form nearly ideal solutions. At T = 300 K, the vapor pressur

Question

Benzene and toluene form nearly ideal solutions. At T = 300 K, the vapor pressures of the pure liquids are, 103 and 32 torr.

a) A liquid mxiture is composed of 3 mol toluene and 2 mol benzene. If the pressure over the mixture at 300k is gradually reduced, at what pressure does the first vapor form?

b) What is the compostion of the first trace of vapor formed?

c) If the pressure is reduced further, what is the composition of the last trace of liquid?

d) At what Pressure does the last trace of liquid disappear?

e) What will be the pressure, the composition of the liquid, and the composition of the vapor when one mole of the mixture has been vaporized?

Explanation / Answer

Since the mole fractions of benzene and toluene in the vapor phase are equal, they each have a value of 0.5 and

the vapor pressure of each substance in the gas phase is the same.

?(benzene) =

P(benzene)

P(total)

= ?(toulene) =

P(toluene)

P(total)

; Pben = Ptol

Pben = ?(benzene) x P(pure benzene) = ?(toluene) x P(pure toluene) and ?(toluene) = 1

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