1. RNA polymerase opens a DNA double-helix in a gene ready to be transcribed by
ID: 82255 • Letter: 1
Question
1. RNA polymerase opens a DNA double-helix in a gene ready to be transcribed by breaking the hydrogenbonds between the complementary bases. Part of the base sequence of one side of this helix, the non-template
(“coding”) strand is:5’-GAG AGC GAT CTA CGC ACG AAG TAC TAA ACA-3’
Start by typing 3’- and single space and then carefully type the sequence of bases in the template strand of DNAthat is complementary to the above strand. End by typing -5’
Use all capital letters. For ease of reading, type one space after every three bases like above (only 1 space, not multiplespaces). In real DNA there is no ‘space’ punctuation between consecutive bases or sets of bases.
2. CAREFULLY type the sequence of bases in the mRNA that would be transcribed from the DNAsequence you typed in question 1. It should be complementary to the strand you typed as your answer to (1). Startyour primary transcript with 5’- and end it with -3’
Use all capital letters. For ease of reading, type one space after every three bases. In real RNA there is no ‘space’ punctuationbetween consecutive bases or sets of bases.
3. CAREFULLY type the sequence of amino acids that would be translated from the pre-mRNA you typed in(2) assuming the pre-mRNA is an exon. For the genetic code see your Ch14 lecture notes (or textbook).Abbreviate each amino acid using the first 3 letters. For example, proline is abbreviated PRO (exceptions:Asparagine = ASN; aspartic acid = ASP; Glutamine = GLN, Glutamic Acid = GLU).
Start your polypeptide with H2N- (the amino group) and end with -COOH (the carboxyl group).Type a dashbetween each amino acid in your answer, symbolizing the peptide bond (example: SER-PRO-THR). Use all capital letters andinclude no extra words, punctuation, or extra spaces in your answer. If you reach a stop codon assume a release factor arrives but do nottype “release factor” or “stop”, but end with a carboxyl group bonded to the previous amino acid.
Explanation / Answer
Coding strand or non template strand;
5'-GAG AGC GAT CTA CGC ACG AAG TAC TAA ACA-3’.
Non coding or template strand will be ;
3'- CTC TCG CTA GAT GCG TGC TTC ATG ATT TGT-5'.
2) The sequence of bases in the mRNA transcribed will be as;
5'- GAG AGC GAU CUA CGC ACG AAG UAC UAA ACA-3.
3) Sequence of amino acids translated would be;
GLU- SER- ASP- LEU- ARG- THR -LYS-TYR-STOP.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.