Please help with chemistry If the pOH of a solution is 11, what is the hydronium
ID: 823497 • Letter: P
Question
Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 MThe Ka for hydrofluoric acid is 6.9 Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M
The Ka for hydrofluoric acid is 6.9 Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? If the pOH of a solution is 11, what is the hydronium ion concentration? 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M
The Ka for hydrofluoric acid is 6.9 The Ka for hydrofluoric acid is 6.9 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M
Explanation / Answer
1) pOH = 11
=> pH = 3
=>[H+] = 10^-3 M = 1 x 10^-3 M
2) Kb = 10^-14 / 6.9 x 10^-4 = 1.4 x 10^-11
3) pH = 2.34
=> [H+] = 4.57 x 10^-3 M = X
Ka = (4.57 x 10^-3)^2 / 0.13 - 4.57 x 10^-3 = 1.66 x 10^-4
4) 3.8 x 10^-9
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