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Please help with chemistry If the pOH of a solution is 11, what is the hydronium

ID: 823497 • Letter: P

Question

Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M
The Ka for hydrofluoric acid is 6.9 Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M
The Ka for hydrofluoric acid is 6.9 Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? Question 12 options: 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M Please help with chemistry Please help with chemistry If the pOH of a solution is 11, what is the hydronium ion concentration? If the pOH of a solution is 11, what is the hydronium ion concentration? 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M

The Ka for hydrofluoric acid is 6.9 The Ka for hydrofluoric acid is 6.9 10.0 x 10-3 M 2.0 x 10-3 M 11.0 x 10-3 M 1.0 x 10-3 M

Explanation / Answer

1) pOH = 11

=> pH = 3

=>[H+] = 10^-3 M = 1 x 10^-3 M


2) Kb = 10^-14 / 6.9 x 10^-4 = 1.4 x 10^-11


3) pH = 2.34

=> [H+] = 4.57 x 10^-3 M = X

Ka = (4.57 x 10^-3)^2 / 0.13 - 4.57 x 10^-3 = 1.66 x 10^-4


4) 3.8 x 10^-9

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