Volume(mL) Volume(mL) Volume(mL) Absorbance Readings Test Tube 5.00*10^-2 M Fe(N
ID: 823556 • Letter: V
Question
Volume(mL)
Volume(mL)
Volume(mL)
Absorbance Readings
Test Tube
5.00*10^-2 M Fe(NO3)3
5.00 *10^-4 M NaNCS
H2O
1
5
1
4
0.010
2
5
2
3
0.502
3
5
3
2
0.940
4
5
4
1
0.985
5
5
5
0
1.19
Standard solution of "known concentration
0.122
** NEED HELP with the...
1. Molarity of FeNCS2+ in solution of "known concentration"
2. Equilibrium concentration of FeNCS2+
Volume(mL)
Volume(mL)
Volume(mL)
Absorbance Readings
Test Tube
5.00*10^-2 M Fe(NO3)3
5.00 *10^-4 M NaNCS
H2O
1
5
1
4
0.010
2
5
2
3
0.502
3
5
3
2
0.940
4
5
4
1
0.985
5
5
5
0
1.19
Standard solution of "known concentration
0.122
Explanation / Answer
Clearly, NCS- is the limiting reactant, and there are 1x10^-6 moles based on the 2.0 mL of 5x10^-4M solution. The volume of solution is 20. mL The concentration of FeNCS^2+ is 5x10^-5M. Divide the moles of NCS- by the volume in liters. Based on your data, the answer is only good to 1 significant digit.
No. There is only 20 mL. The Fe(NO3)3 is dissolved in a solution of nitric acid, and there are only 10 mL of it. It's not 10 mL of Fe(NO3)3 and 10 mL of HNO3.
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