WRITTE THE BALANCED NET IONIC EQUATION FOR EACH REACTION AND TELL WHETHER THE EL

Question

WRITTE THE BALANCED NET IONIC EQUATION FOR EACH REACTION AND TELL WHETHER THE ELEMENT OR COMPOUND IS AQ, GAS, LIQUID OR SOLID. PLEASE SHOW WORK AND I NEED THE NET IONIC EQUATION!! NOT JUST THE BALANCED EQUATION!!!! STATE NR WHEN NO REACTION!!!!

thiosulfuric acid + lead(II) nitrate rightarrow copper(II) bromide + aluminum nitrate rightarrow hydroiodic acid + calcium chromate rightarrow aqueous ammonia + thiocyanic acid rightarrow aluminum + cadmium sulfate rightarrow nickel(II) chloride + potassium cyanide rightarrow mercury(II) chloride + sodium sulfide rightarrow

Explanation / Answer

1)

Na2S(aq) + 2HCl(aq) ------------> 2NaCl(aq) + H2S(g)

Then, write out the TOTAL IONIC EQUATION
Do this by seperating anything in aqueous solution into its constituant ions...

2Na+(aq) + S2-(aq) + 2H+(aq) + 2Cl-(aq) -----> 2Na+(aq) + 2Cl-(aq) + H2S(g)

Now, you can see that 2Na+(aq) and 2Cl-(aq) occur on both sides of the equation unchanged, they are called spectator ions and do not participate in the reaction.

Spectator ions are left out of the

NET IONIC EQUATION

2H+(aq) + S2-(aq) ----------> H2S(g)

2)

Zn(s) + Cu(NO3)2(aq) => Zn(NO3)2(aq) + Cu(s)

Zn(s) + Cu2+(aq) + 2NO3-(aq) => Zn2+(aq) + 2NO3-(aq) + Cu(s)

NET: Zn(s) + Cu2+(aq) => Zn2+(aq) + Cu(s)

3)

Molecular:

2HNO3(aq) + BaCO3(aq) >>>>>>>>>> Ba(NO3)2(aq) + H2O(l) + CO2(g)

Ionic:

2H+(aq) + NO3-(aq) + Ba2+(aq) + CO3 2-(aq) >>>>>>>>>>>> Ba2+(aq) + NO3-(aq) + H2O(l) + CO2(g)

Net Ionic:

2H+(aq) + CO3 2-(aq) >>>>>>>>>>>>> H2O(l) + CO2(g)

4)

The balanced equation for your reaction is:

CaCl2 (aq) + 2 NH4OH (aq) ---> Ca(OH)2 (s) + 2 NH4Cl (aq)

(ammonium hydroxide can also be written NH3.H2O but is easier understood this way)


The full ionic equation is therefore:

Ca^(2+) + 2 Cl^(-) + 2 NH4^(+) + 2 OH^(-) ----> Ca(OH)2 (s) + 2 NH4^(+) + 2 Cl^(-)

(all the ions are of course in the aqueous phase so I left out the states to keep it easy to read)



To get the net ionic equation you simply cancel like terms from both sides:

The chloride (Cl -) and ammonium (NH4 +) ions exist in the same form on both sides and are therefore unchanged in the net reaction. you therefore remove them.

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