%3Cp%3E%3Cspan%20class%3D%22c1%22%3EA%20solution%20is%20prepared%20by%20dissolvi
ID: 824272 • Letter: #
Question
%3Cp%3E%3Cspan%20class%3D%22c1%22%3EA%20solution%20is%20prepared%20by%20dissolving%0A0.13%3C%2Fspan%3E%3Cspan%20class%3D%22replace-insert%20done%20c1%22%20id%3D%0A%22yui_3_11_0_24_1394912945268_13%22%3E%3Cspan%20class%3D%0A%22type-specific%22%3E%3Cspan%20class%3D%22MathJax%20c7%22%20id%3D%0A%22MathJax-Element-1-Frame%22%3E%3Cspan%20class%3D%22math%20c3%22%20id%3D%0A%22MathJax-Span-1%22%3E%3Cspan%20class%3D%22c5%22%3E%3Cspan%20class%3D%22c4%22%3E%3Cspan%20class%3D%0A%22mrow%20c3%22%20id%3D%22MathJax-Span-2%22%3E%3Cspan%20class%3D%22texatom%20c3%22%20id%3D%0A%22MathJax-Span-3%22%3E%3Cspan%20class%3D%22mrow%20c3%22%20id%3D%0A%22MathJax-Span-4%22%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-5%22%3Em%3C%2Fspan%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-6%22%3Eo%3C%2Fspan%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-7%22%3El%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3Cspan%20class%3D%22c1%22%3E%20of%0Aacetic%20acid%20and%200.13%3C%2Fspan%3E%3Cspan%20class%3D%22replace-insert%20done%20c1%22%20id%3D%0A%22yui_3_11_0_24_1394912945268_23%22%3E%3Cspan%20class%3D%0A%22type-specific%22%3E%3Cspan%20class%3D%22MathJax%20c7%22%20id%3D%0A%22MathJax-Element-2-Frame%22%3E%3Cspan%20class%3D%22math%20c3%22%20id%3D%0A%22MathJax-Span-8%22%3E%3Cspan%20class%3D%22c5%22%3E%3Cspan%20class%3D%22c4%22%3E%3Cspan%20class%3D%0A%22mrow%20c3%22%20id%3D%22MathJax-Span-9%22%3E%3Cspan%20class%3D%22texatom%20c3%22%20id%3D%0A%22MathJax-Span-10%22%3E%3Cspan%20class%3D%22mrow%20c3%22%20id%3D%0A%22MathJax-Span-11%22%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-12%22%3Em%3C%2Fspan%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-13%22%3Eo%3C%2Fspan%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-14%22%3El%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3Cspan%20class%3D%22c1%22%3E%26nbsp%3Bof%0Aammonium%20chloride%20in%20enough%20water%20to%20make%0A1.0%26nbsp%3B%3C%2Fspan%3E%3Cspan%20class%3D%22replace-insert%20done%20c1%22%20id%3D%0A%22yui_3_11_0_24_1394912945268_26%22%3E%3Cspan%20class%3D%0A%22type-specific%22%3E%3Cspan%20class%3D%22MathJax%20c7%22%20id%3D%0A%22MathJax-Element-3-Frame%22%3E%3Cspan%20class%3D%22math%20c3%22%20id%3D%0A%22MathJax-Span-15%22%3E%3Cspan%20class%3D%22c9%22%3E%3Cspan%20class%3D%22c8%22%3E%3Cspan%20class%3D%0A%22mrow%20c3%22%20id%3D%22MathJax-Span-16%22%3E%3Cspan%20class%3D%22texatom%20c3%22%20id%3D%0A%22MathJax-Span-17%22%3E%3Cspan%20class%3D%22mrow%20c3%22%20id%3D%0A%22MathJax-Span-18%22%3E%3Cspan%20class%3D%22mi%20c2%22%20id%3D%0A%22MathJax-Span-19%22%3EL%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3C%2Fspan%3E%3Cspan%20class%3D%22c1%22%3Eof%0Asolution.%3C%2Fspan%3E%3C%2Fp%3E%0A%3Cdiv%20class%3D%22text%20edible%20c10%22%3EFind%20the%20concentration%20of%20ammonia%20in%0Athe%20solution.%3C%2Fdiv%3E%0A%3Cdiv%20class%3D%22instructions%20edible%20c11%22%3E%3Clabel%3EExpress%20your%20answer%0Ausing%20two%20significant%20figures%3C%2Flabel%3E%3C%2Fdiv%3E%0AExplanation / Answer
If you mean by "concentration of ammonia in solution" [NH3], that will be nearly zero.
But [NH4+] = .13M
because a reaction will happen between acetic acid and ammonia.
nh4+ concentration will be 0.13 M
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