Calculate the pH for each of the following cases in the titration of 50.0 mL of

Question

Calculate the pH for each of the following cases in the titration of 50.0 mL of 0.130 M HClO(aq) with 0.130 M KOH(aq). The ionization constant for HClO can be found here. https://sites.google.com/site/chempendix/ionization

Calculate the pH for each of the following cases in the titration of 50.0 mL of 0.130 M HCIO(ag) with 0.130 M KOH(aq). The ionization constant for HCIO can be found here. before addition of any KOH after addition of 25.0 mL of KOH after addition of 35.0 mL of KOH after addition of 50.0 mL of KOH after addition of 60.0 mL of KOH

Explanation / Answer

after addition of 50 ml KOH,

moles of KOH = 60 * 0.13 = 7.8 mmol

moles of HClO = 50 * 0.13 = 6.5 mmol

occurred hydrolysis solution,

pH = 0.5(14 + pKa + log [base conjugate])

pH = 0.5(14 + (- log (4 * 10^-8)) + log (7.8/(50 + 50)))

pH = 10.145

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.