Question
The metabolic oxidation of glucose, C 6H 12O 6
Two researchers are constructing confidence interval for mean mu from the same dataset. First researcher constructs a 95% confidence interval. The second researcher constructs a 90% confidence interval. Which statements are correct among the following set of statements ? (Select all that apply) If the true value of mu is going to be outside the 95% confidence interval, it is always going to be outside the 90% confidence interval. To answer this question, we need to know the value of sample mean and sample size. If the true value of mu lies within the 95% confidence interval, it is always going to be inside the 90% confidence interval. If the true value of mu is going to be inside the 90% confidence interval, it may lie outside the 95% confidence interval. If the true value of mu is going to lie outside the 90% confidence interval, it may still be inside the 95% confidence interval. Which of the following options are true about the use of central limit theorem? (Select all that apply) It is useful to construct a confidence interval for sample mean when we have 30 or more subjects in the sample. It is useful to find the mean and variance of sample mean when we have 30 or more subjects in the sample. It is useful to construct a confidence interval for population mean approximately when we have 30 or more subjects. It is useful to find the approximate sampling distribution of sample mean when have 30 or more subjects in the sample. It is useful to find the mean and variance of sample mean when we have less than 30 subjects in the sample. It is useful to know that sample mean is same as population mean when we have 30 or more subjects in the sample. The number of patients in a walk-in medical clinic per day follows a probability distribution with mean 19 and standard deviation 3.50. on 49 randomly chosen days, data were collected on how many patients visit that clinic. Check all correct statements from the set of following statements. (Select all that apply.) The central limit theorem implies that the probability of average number of patients during those 49 days being greater than 20 is 0.0228. We do not need central limit theorem to conclude that mean of the average number of patients during those 49 days is 19. We need central limit theorem to conclude that the variance of the average number of patients during those 49 days is 0.25. The central limit theorem implies that the probability of the number of patients in one of those 49 days being greater than 20 is 0.0228 We cannot apply central limit theorem here because the mean is 19 which is less than 30. The central limit theorem implies that the probability of the number of patients in one of those 49 days being greater than 12 is 0.9772.
Explanation / Answer
(A) C6H12O6 + 6 O2 => 6 CO2 + 6 H2O
Moles of glucose = mass/molar mass of glucose
= 25.5/180.16 = 0.14154 mol
Moles of CO2 = 6 x moles of glucose
= 6 x 0.14154 = 0.84925 mol
Ideal gas equation: PV = nRT
Volume of CO2 = V = nRT/P
= 0.84925 x 0.08206 x (273.15 + 37)/0.960
= 22.5 L
(B) C6H12O6 + 6 O2 => 6 CO2 + 6 H2O
Moles of glucose = mass/molar mass of glucose
= 53/180.16 = 0.29418 mol
Moles of O2 = 6 x moles of glucose
= 6 x 0.29418 = 1.7651 mol
Ideal gas equation: PV = nRT
Volume of O2 = V = nRT/P
= 1.7651 x 0.08206 x 298/1.00
= 43.2 L (approximately 43 L)
