When propanol (CH3CH2CH2OH) is combusted, such as when in a gasoline blend, the

Question

When propanol (CH3CH2CH2OH) is combusted, such as when in a gasoline blend, the following reaction occurs:

2CH3CH2CH2OH (l) +9O2 (g) = 6CO2 (g) + 8H2O (g)

Based on standard free energies of formation (given), what is the standard free energy of change for this reaction?

Substance                              kJ / mol

CH3CH2CH2OH                    -360.5

O2                                             0

CO2                                        -394.4

H2O                                         -228.6

Explanation / Answer

= products - reactents

= [8*(-228.6) + 6*(-394.4)] -[2(-360.5)]

= -3474.2 Kj/mol

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