The molar enthalpy of a binary liquid mixture of species 1 and 2 is given by: h

Question

The molar enthalpy of a binary liquid mixture of species 1 and 2 is given by: h = 1500 x1 + 800 x2 + (25.0 x1 + 35.0 x2 - 11.86x1x2)T[j/mol] where Tis the temperature in [K]. This expression is valid in the temperature range from 280 K to 360 K. Please answer the following questions: You wish to dilute and cool a process stream containing 50 mol% species I and 50 mol% species 2. Consider the adiabatic mixing of a stream a (containing 50 mol% species 1 and 50 mol% species 2) with a molar flow rate of 2 mol/s at 75 degree C and I bar with a stream b of pure species 1 flowing at a rate of 3 mol/s at 20 degree C and 1 bar. What is the exit temperature of the outlet stream? You may assume steady-state. What is the partial molar enthalpy of species 1, H-1 , in stream d? What is the partial molar enthalpy of species 1 at infinite dilution, H- infinity 1 at 75 degree C? Would the final temperature you calculate be higher or lower than that calculated in Part A if you didn't include the "mixing" effects of the unlike interactions? Consider a system in which liquid water is in phase equilibrium with wet air at 25 degree C and

Explanation / Answer

Part A is 52 deg C

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