Consider the following line notation and half reactions. A. Sketch the complete

Question

Consider the following line notation and half reactions.
A. Sketch the complete cell.
B. Label the anode and cathode.
C. Write the anode half reaction and the cathode half reaction.
D. Give a net balanced reaction.
E. Calculate Ecell.
F. What is the numerical value of K for the reaction you wrote for part D?
G. What would Ecell be if the solution were allowed to stand for an extended period of time, such that
not just the half cells were at equilibrium but that the whole cell is at equilibrium?
Pt(s) | Cu2S (0.258 M) | Cu(s) || Pb(NO3)4 (0:10 M), Pb(NO3)2 (0.071 M) | Pt(s)

Explanation / Answer

E

Ecell= E*cell - (0.0592/n)logQ

E*cell = E(Cu) - E(Mn)     : E() represents the half reaction potentials

G Ecell will be zero as all the cherges are at eqilibrium and reaction is fully completed and all charges neutralised

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