The following questions all concern the redox equation: 2MnO4,- + 5H2C2O4 + 6H+-

Question

The following questions all concern the redox equation: 2MnO4,- + 5H2C2O4 + 6H+-->10CO2 + 2Mn,2+ +8H2O
What is the symbol for the element that is being reduced?

What is the symbol for the element that is being oxidized?

Which reactant is the reducing agent? Enter your answer as it is written in the above equation without coefficients, for example, would be entered Cr2O72-.

What is the change in the oxidation number of the element that is reduced? Enter your answer as a number with the correct sign, for example, -3 or +2.

Explanation / Answer

Mn reduced

C oxidised

H2C2O4 reducing agent

+7 to +2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.