Which of the following statements is incorrect ? Select one: a. Acid-base reacti

Question

Which of the following statements is incorrect ?

Select one:

a. Acid-base reactions involve a transfer of protons; redox reactions, a transfer of electrons

b. Just as most acid-base reactions in solution reach a state of equilibrium, in which appreciable concentrations of the acids and their conjugate bases are present, so most aqueous redox reactions reach a state of equilibrium, with the favoured side of the reaction depending on the oxidizing agent-reducing agent strength.

c. Unlike acid-base reactions, where certain species can either donate or accept protons and thereby behave as an acid in one reaction and a base in another, in redox reactions a given species will always either accept or donate electrons, so cannot act as an oxidizing agent in one reaction and a reducing agent in another

d. Just as acids and bases may be classified as "strong" or "weak" depending on how readily they donate or accept protons, the strengths of oxidizing and reducing agents may be compared according to their tendencies to attract or release electrons

e. In both redox and acid-base reactions, the reactants are given special names to indicate their roles in the transfer process

A Br

Explanation / Answer

1)Unlike acid-base reactions, where certain species can either donate or accept protons and thereby behave as an acid in one reaction and a base in another, in redox reactions a given species will always either accept or donate electrons, so cannot act as an oxidizing agent in one reaction and a reducing agent in another

2) an electron pair donor

3) a strong electrolyte

4). Nitric acid, HNO3

5)NO3- (aq) + Cl- (aq)

6) Fe22+ (aq) + SO32- (aq)

7)NH4+ (aq

8). pH = 10-11, pOH = 10-3

9). Tastes sour.

10)ince pH + pOH = 14
when the pH = 4.5
the pOH must be 9.5


converting pH into concentrations, we do a 10^x on a changed sign of the pH:
[H+] = 10^-4.5
[H+] = 3.16 X 10^-5
your answer, rounded to 1 sig figs would be
[H+] = 3 X 10^-5


converting pOH into concentrations, we do a 10^x on a changed sign of the pOH:
[OH-] = 10^-9.5
[OH-] = 3.16 X 10^-10
your answer, rounded to 1 sig figs would be
[OH-] = 3 X 10^-10



another thought worth remembering is that
[H+] times [OH-] = 1 X 10^-14
so
when [H+] = 3.16 X 10^-5
...
[[OH-] = (1 X 10^-14) / ((3.16 X 10^-5)
[OH-] = 3.16 X 10-10

again since your data "pH = 4.5" has only 1 sig fig...
lyour answers round off to
[H+] = 3 X 10^-5
[OH-] = 3 X 10^-10

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