The enthalpy of combustion (Delta H degree C) of ethylcyclobutane (C6H12) is -40

Question

The enthalpy of combustion (Delta H degree C) of ethylcyclobutane (C6H12) is -4017.10 kJ/mol. Using the appropriate information given below, calculate the enthalpy of formation (Delta H degree f), in kJ/mol, for ethylcyclobutane. Report your answer to two decimal places. Delta H degree f (C02 (g)) = -393.51 kJ/mol Delta H degree f (H20 (I)) = -285.83 kJ/mol Determine the mass (in g) of ethylcyclobutane produced, if Delta H degree was determined to be -21.81 kJ during an experiment in which ethylcyclobutane was formed. Report your answer to three significant figures.

Explanation / Answer

C6H12 + 9O2 -------------> 6CO2 + 6H2O

Enthalpy of formation = Enthalpy of Products - Enthalpy of reactants

= 6 ( -393.51) + 6 ( -285.83) - [ -4017.10 ]

= -58.94 kJ / mol is the enthalpy of formation of Ethylcyclobutane

Now,if H = -21.81, then:

21.81 / 58.94 = 0.37moles of the compound are formed.

Hope this helps.

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